There are 2*8*5*52 = 4160 clock
hours per year
There are 4160 * .80 = 3328 effective hours per year
a) Standard capacity requirements for the three products at given lot sizes:
A: .05 + 1/60 = .06667 hours/unit
B: .20 + 4.5/80 = .25625 hours/unit
C: .05 + 8.2/120 = .11833 hours/unit
|
|
Pessimistic |
Expected |
Optimistic |
|
A |
1000 |
1200 |
1666.667 |
|
B |
2562.5 |
3331.25 |
4356.25 |
|
C |
2011.6 |
2958.25 |
4733.2 |
|
Total hrs needed |
5574.1 |
7489.5 |
10756.12 |
|
No of machines |
5574.1/3328=1.67 |
7489.5/3328=2.25 |
10756.12/3328=3.23 |
|
In whole numbers |
2 |
3 |
4 |
b) With 20% capacity augmentation (through short-term means such as
over time) there will be 3328*3* 1.2 = 11980.8 hours which leads to
1224.68 hours of excess capacity (negative gap).
Without such short term mesures there is 10756-3328*3 = 772
hours of capacity gap.
|
|
Kites |
Wind Socks |
Demand |
30,000 |
12,000 |
Lot Size |
20 |
70 |
|
Standard Hours/unit |
3.0/20 + 0.3 = 0.45/unit |
4.0/70 + 1.0 = 1.057/units |
|
Standard hours needed |
13,500 |
12,686 |
Or a total of 26,186 hours are needed.
Clock hours per machine per year: 2 * 8 * 2000 = 3,200
Effective hrs/mach/year 3,200* .75 = 2,400 hours
Therefore 26,186/2,400 = 10.91 or 11 machines are needed. Or 7 new machines are needed