Feb 23, 2002
Notes for Lecture
Notes for Lecture #15
Vector potentials in magnetostatics
The vector potential corresponding to a current density
distribution J(r) is given by
A(r) = |
m0 4 p
|
|
ó õ
|
d3r¢ |
J(r¢) |r - r¢|
|
. |
| (1) |
This expression is useful if the current density J(r) is
confined within a finite region of space. Consider the following
example corresponding to a rotating charged sphere of radius a,
with r0 denoting the uniform charge density within the
sphere and w denoting the angular rotation of the
sphere:
In order to evaluate the vector potential (1) for this
problem, we can make use of the expansion:
|
1 |r - r¢|
|
= |
å
lm
|
|
4 p 2 l +1
|
|
r < l r > l+1
|
Ylm( |
^ r
|
)Ylm*( |
^ r¢
|
). |
| (3) |
Noting that
r¢ = r¢ |
æ ú
Ö
|
|
|
æ ç ç
ç è
|
Y1-1( |
^ r¢
|
) |
Ö2
|
+ Y11( |
^ r¢
|
) |
Ö2
|
+ Y10( |
^ r¢
|
) |
^ z
|
ö ÷ ÷
÷ ø
|
, |
| (4) |
we see that the angular integral result takes the simple form:
|
ó õ
|
dW¢ |
å
m
|
Ylm( |
^ r
|
)Ylm*( |
^ r¢
|
) r¢ = |
r¢ r
|
r dl1. |
| (5) |
Therefore the vector potential for this system is:
A(r) = |
m0 r0 w×r 3 r
|
|
ó õ
|
a
0
|
dr¢ r¢3 |
r < r > 2
|
, |
| (6) |
which can be evaluated as:
A(r) = |
ì ï ï ï ï ï í
ï ï ï ï ï î
|
|
|
m0 r0 w× r 3
|
|
æ ç
è
|
|
a2 2
|
- |
3 r2 10
|
ö ÷
ø
|
|
| |
| |
| |
|
. |
| (7) |
As another example, consider the current associated with an
electron in a spherical atom.
In this case, we assume that the current density is due to an
electron in a bound atomic state with quantum numbers |n l ml ñ, as described by a wavefunction
ynlml(r), where the azimuthal quantum number ml is associated with
a factor of the form ei ml f. For such a wavefunction the quantum
mechanical current density operator can be evaluated:
J(r) = |
-e (h/2p) 2 me i
|
(ynlml*Ñynlml-ynlml Ñynlml* ). |
| (8) |
Since the only complex part of this wavefunction is associated
with the azimuthal quantum number, this can be written:
J(r) = |
-e (h/2p) 2 me i rsinq
|
|
æ ç
è
|
ynlml* |
¶ ¶f
|
ynlml-ynlml |
¶ ¶f
|
ynlml* |
ö ÷
ø
|
|
^ f
|
= |
me r sinq
|
|ynlml|2. |
| (9) |
where me denotes the electron mass and e denotes the
magnitude of the electron charge.
For example, consider
the |nlm = 211ñ state of a H atom:
J(r¢) = |
-e(h/2p) 64 m pa5
|
e-r¢/a |
^ z
|
×r¢, |
| (10) |
where a here denotes the Bohr radius. Using arguments similar to
those above, we find that
A(r) = |
192 mpa5 r
|
|
ó õ
|
¥
0
|
dr¢ r¢3 e-r¢/a |
r < r > 2
|
. |
| (11) |
This expression can be integrated to give:
A(r) = |
8 mpr3
|
|
é ê
ë
|
1 - e-r/a |
æ ç
è
|
1 + |
r a
|
+ |
r2 2 a2
|
+ |
r3 8 a3
|
ö ÷
ø
|
ù ú
û
|
. |
| (12) |
File translated from TEX by TTH, version 2.20.
On 23 Feb 2002, 14:03.