Feb 23, 2002

Notes for Lecture Notes for Lecture #17

Derivation of the hyperfine interaction

Magnetic dipole field

These notes are very similar to the notes for Lecture #12 on the electric dipole field.

The magnetic dipole moment is defined by

m = 1
2
ó
õ
d3r¢ r¢ ×J(r¢),
(1)
with the corresponding potential
A(r) = m0
4p
m × ^
r
 

r2
,
(2)
and magnetostatic field
B(r) = m0
4p
ì
ï
í
ï
î
3 ^
r
 
(m · ^
r
 
) - m

r3
+ 8p
3
m d3(r) ü
ï
ý
ï
þ
.
(3)

The first terms come form evaluating Ñ×A in Eq. 2. The last term of the field expression follows from the following derivation. We note that Eq. (3) is poorly defined as r® 0, and consider the value of a small integral of B(r) about zero. (For this purpose, we are supposing that the dipole m is located at r = 0.) In this case we will approximate

B(r » 0) » æ
è
ó
õ


sphere 
B(r) d3r ö
ø
d3(r).
(4)

First we note that

ó
õ


r £ R 
B(r) d3r = R2 ó
õ


r = R 
^
r
 
×A(r)   dW.
(5)

This result follows from the divergence theorm:

ó
õ


vol 
Ñ·V d3r = ó
õ


surface 
V · dA.
(6)
In our case, this theorem can be used to prove Eq. (5) for each cartesian coordinate of Ñ×A since Ñ×A = [^(x)] ( [^(x)] ·(Ñ× A) ) + [^(y)] ( [^(y)] ·(Ñ×A) ) + [^(z)] ( [^(z)] ·(Ñ×A) ). Note that [^(x)] ·(Ñ×A) = -Ñ·([^(x)] ×A) and that we can use the Divergence theorem with V º [^(x)] ×A(r) for the x- component for example:
ó
õ


vol 
Ñ·( ^
x
 
×A) d3r = ó
õ


surface 
( ^
x
 
×A) · ^
r
 
dA = ó
õ


surface 
(A × ^
r
 
) · ^
x
 
dA.
(7)
Therefore,
ó
õ


r £ R 
(Ñ×A) d3r = - ó
õ


r = R 
(A × ^
r
 
) ·( ^
x
 
^
x
 
+ ^
y
 
^
y
 
+ ^
z
 
^
z
 
) dA = R2 ó
õ


r = R 
( ^
r
 
×A) dW
(8)
which is identical to Eq. (5). We can use the identity (as in Lecture Notes 12),
ó
õ
dW
^
r
 

|r - r¢|
= 4 p
3
r <
r > 2
   ^
r¢
 
.
(9)
Now, expressing the vector potential in terms of the current density:
A(r) = m0
4 p
ó
õ
d3r J(r¢)
|r - r¢|
,
(10)
the integral over W in Eq. 5 becomes
R2 ó
õ


r = R 
( ^
r
 
×A) dW = 4 pR2
3
m0
4 p
ó
õ
d3r¢    r <
r > 2
   ^
r¢
 
×J(r¢).
(11)
If the sphere R contains the entire current distribution, then r > = R and r < = r¢ so that (11) becomes
R2 ó
õ


r = R 
( ^
r
 
×A) dW = 4 p
3
m0
4 p
ó
õ
d3r¢   r¢ ×J(r¢) º 8 p
3
m0
4 p
m,
(12)
which thus justifies the so-called ``Fermi contact'' term in Eq. 3.

Magnetic field due to electrons in the vicinity of a nucleus

In Lecturenotes #15, we showed that the current density associated with an electron in a bound state of an atom as described by a quantum mechanical wavefunction ynlml(r) can be written:

J(r) =
-e (h/2p) ml ^
f
 

me r sinq
|ynlml(r)|2.
(13)

In the following, it will be convenient to represent the azimuthal unit vector [^(f)] in terms of cartesian coordinates:

^
f
 
= - sinf ^
x
 
+ cosf ^
y
 
=
^
z
 
×r

r sinq
.
(14)

The vector potential for this current density can be written

A(r) = - m0
4p
e (h/2p)
me
 ml   ó
õ
d3r¢
^
z
 
×r¢

|r - r¢|
|ynlml(r¢)|2

r¢2 sin2q¢
(15)

We want to evaluate the magnetic field B = Ñ×A in the vicinity of the nucleus (r ® 0). Taking the curl of the Eq. 15, we obtain

B(r) = m0
4p
e (h/2p)
me
 ml   ó
õ
d3r¢
(r-r¢) ×( ^
z
 
×r¢)

|r - r¢|3
|ynlml(r¢)|2

r¢2 sin2q¢
(16)
Evaluating this expression with (r ® 0), we obtain
B(0) = - m0
4p
e (h/2p)
me
 ml   ó
õ
d3r¢
r¢ ×( ^
z
 
×r¢)

r¢3
|ynlml(r¢)|2

r¢2 sin2q¢
(17)
Expanding the cross product and expressing the result in spherical polar coordinates, we obtain in the numerator [^(r)]¢ ×([^(z)] ×[^(r)]¢) = [^(z)](1-cos2q¢)-[^(x)]cosq¢sinq¢cosf¢-[^(y)]cosq¢sinq¢sinf¢).

In evaluating the integration over the azimuthal variable f¢, the [^(x)] and [^(y)] components vanish which reduces to

B(0) = - m0
4p
e (h/2p)
me
 ml   ó
õ
d3r¢
^
z
 
r¢2 sin2q¢

r¢3
|ynlml(r¢)|2

r¢2 sin2q¢
(18)
and
B(0) = -
m0 e (h/2p) ml ^
z
 

4 pme
ó
õ
d3r¢|ynlml|2 1
r¢3
º - m0 e
4 pme
Lz ^
z
 

á
1
r¢3

ñ
.
(19)


File translated from TEX by TTH, version 2.20.
On 23 Feb 2002, 19:22.