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Balancing Redox Equations in Base |
Once you have master balancing redox reactions in acid, it is easy to do it in base. This example will balance the same reaction as we did for acidic solutions.
| I. Balance the equation as if in an acid solution | |
| Step 1: | Separate in half reactions. |
| Step 2: | In each half reaction, balance all elements except O & H. |
| Step 3: | Balance O by adding H2O. |
| Step 4: | Balance H by adding H+. |
| Step 5: | Balance charges by adding e-. |
| Step 6: | Multiply all coefficients in 1 or both half reactions by an integer to get the number of e- in the two half reactions equal. |
| Step 7: | Add the 2 half reactions together & cancel out any species that appear on both sides of net reaction. |
| Step 8: | Check that charges and atoms are balanced. |
| II. Balance the equation with base | |
| Step 9: | Identify the number of proton (H+) in the acidic answer. Add the same number of OH- ions to BOTH sides of the equation. |
| Step 10: | If H+ and OH- appear on the same side of the equation, they will react in a 1:1 ratio to form H2O. |
| Step 11: | Cancel out water molecules that appear on both sides of the equation. |
| Step 12: | Check that charges and atoms are balanced. |
Update 2020-11: The Adobe Shockwave is no longer supported but I have received requests to access this interactive tutorial. So now I have made this interactive tutorial available as an executable for Windows.
Click here to download the executable. Remember where you download the file to. After it has finished downloading, double-click on the .exe file to run it. It does not require Internet access to run.
Please email me if you need an executable for MacOS.