Balancing Redox Equations in Base
Once you have master balancing redox reactions in acid, it is easy to do it in base. This example will balance the same reaction as we did for acidic solutions.
Interactive Example: an online interactive tutorial to show you step-by-step how to apply the steps described below.
|I. Balance the equation as if in an acid solution|
|Step 1:||Separate in half reactions.|
|Step 2:||In each half reaction, balance all elements except O & H.|
|Step 3:||Balance O by adding H2O.|
|Step 4:||Balance H by adding H+.|
|Step 5:||Balance charges by adding e-.|
|Step 6:||Multiply all coefficients in 1 or both half reactions by an integer to get the number of e- in the two half reactions equal.|
|Step 7:||Add the 2 half reactions together & cancel out any species that appear on both sides of net reaction.|
|II. Balance the equation with base|
|Step 8:||Identify the number of proton (H+) in the acidic answer.
Add the same number of OH- ions to BOTH sides of the equation.
|Step 9:||If H+ and OH- appear on the same side of the equation, they will react in a 1:1 ratio to form H2O.|
|Step 10:||Cancel out water molecules that appear on both sides of the equation.|
|Step 11:||Check that charges and atoms are balanced.|